Friday, April 6, 2007

What I learned in Lab 9

In lab 9 on Friday, we learned how Excel works to analyze large groups of data using data analysis. The lab helped teach us how to use that equations for finding the slope and how to use Excel more in dept. With Excelto help us, the equations are performed with more ease. With Excel, you are able to figure out even more information in a much shorter time than just by using the equations on paper and solving them yourself.

Lab 9 also dealt with inductive modeling, I find this very useful, especially when studying a sample of a large number.

Friday, March 23, 2007

Thursday, March 8, 2007




The function of this curcuit is to pick the one or the other and then take the not of that...which gives you only the teo that are both false or both true.

Friday, February 23, 2007

Positional vs. Non-Positional

The difference between the positional and non-positional number systems is simple. The positional system is based on exactly where the numbers are in the sequence of numbers; as opposed to non-positional number systems where the position of the number isn't a determining factor. An expamle of the non-positional system would be roman numerals.

Decimal to Binary

You need to take 529 and start dividing it by two, keeping track of the quotient and the remainder.

Decimal - Quotient -- Remainder ------- Binary
529 ----- 264 ------ 1 ------------------ 1
264 ----- 132 ------ 0 ----------------- 01
132 ----- 66 ------ 0 ---------------- 001
66 ------ 33 ------ 0 --------------- 0001
33 ------ 16 ------ 1 -------------- 10001
16 ------ 8 ------- 0 ------------- 010001
8 ------- 4 ------- 0 ------------ 0010001
4 ------- 2 ------- 0 ----------- 00010001
2 ------- 1 ------- 0 ---------- 000010001
1 ------- 0 ------- 1 --------- 1000010001

Therefore the binary number for 529 is 1000010001.

Binary to decimal

To convert 11001010 to a decimal number you need to align 11001010 with the powers of two starting at the right side. Always start on the right side and start with 2^0 and move upwards.

Example:

2^7 2^6 2^5 2^4 2^3 2^2 2^1 2^0
1 1 0 0 1 0 1 0

After this you need to figure out the total of the numbers with a 1 under them, add all of these together.

128+64+8+2 You get 202.